Returning value by ref does not create a ref. Is this intentional?

[Tejas]

On Wednesday, 5 January 2022 at 08:58:44 UTC, Dennis wrote:
> On Wednesday, 5 January 2022 at 05:38:45 UTC, Tejas wrote:
>> The entire reason I wanted to get a `ref` was so that I can 
>> avoid the `*` :(
>
> I don't know what the real code behind the reduced example is, 
> but maybe you can structure your code such that the subsequent 
> modification `c = 10` happens in its own function. Then you can 
> pass the result of `func(a)` to that function by `ref`.

There isn't any complex code behind this.

I was simply trying to emulate C++'s `int&`(or `T&` in general)