passing a variadic parameter to randomSample
WebFreak001
d.forum at webfreak.org
Tue Jan 25 12:29:40 UTC 2022
On Tuesday, 25 January 2022 at 09:48:25 UTC, forkit wrote:
> so I'm trying to write (or rather learn how to write) a
> 'variadic template function', that returns just one of its
> variadic parameter, randomly chosen.
>
> But can't get my head around the problem here :-(
>
> .. Error: template `std.random.randomSample` cannot deduce
> function from argument types `
>
> // --
>
> module test;
> import std;
>
> string RandomChoice(R...)(R r)
> {
> auto rnd = MinstdRand0(42);
> return r.randomSample(1, rnd).to!string;
> }
>
> void main()
> {
> writeln( RandomChoice("typeA", "typeB", "typeC") );
> }
>
> // --
With R... each value could be of different type, so passing
`RandomChoice("typeA", 4)` would break the current code.
I think there are 2 different ways that can solve this elegantly:
1) restrict the parameters to all be the same parameter type:
```d
string RandomChoice(T)(T[] r...)
{
auto rnd = MinstdRand0(42);
return r.randomSample(1, rnd).to!string;
}
```
and code compiles with no changes. Instead of using
.to!string you could also return the parameter type itself if you
want to get the value itself:
```d
T RandomChoice(T)(T[] r...)
{
auto rnd = MinstdRand0(42);
return r.randomSample(1, rnd).front;
}
```
2) generate a random number between 0 and `r.length`, add a
switch case and dynamically generate a case for each number
(static foreach) and return the processed value using .to!string:
```d
string RandomChoice(R...)(R r)
{
auto rnd = MinstdRand0(42);
switch (uniform(0, R.length, rnd))
{
static foreach (i, value; r)
{
case i: // this code is duplicated for each
parameter
// use this if you want to support different
argument types
return value.to!string;
}
default: assert(false);
}
}
```
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