DIP1000
Loara
loara at noreply.com
Fri Jun 24 17:53:07 UTC 2022
On Thursday, 23 June 2022 at 16:08:01 UTC, Ola Fosheim Grøstad
wrote:
> How am I supposed to write this:
>
> ```d
> import std;
> @safe:
>
> struct node {
> node* next;
> }
>
> auto connect(scope node* a, scope node* b)
> {
> a.next = b;
> }
>
> void main()
> {
> node x;
> node y;
> connect(&x,&y);
> }
>
> ```
>
>> Error: scope variable `b` assigned to non-scope `(*a).next`
Why you should use `scope` here? A `scope` pointer variable may
refer to a stack allocated object that may be destroyed once the
function returns.
Since a linked list should not contain pointers to stack
allocated data you should avoid entirely the `scope` attribute
and use instead `const`.
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