Parameters declared as the alias of a template won't accept the arguments of the same type.
ag0aep6g
anonymous at example.com
Mon May 2 20:16:04 UTC 2022
On 02.05.22 21:17, Stanislav Blinov wrote:
> On Monday, 2 May 2022 at 16:29:05 UTC, Loara wrote:
[...]
>> ```d
>> template MyAlias(T){
>> alias MyAlias = int;
>> }
>>
>> T simp(T)(MyAlias!T val){
>> return T.init;
>> }
>>
>> int main(){
>> simp(3);//Impossible to deduce T
>
> Why? That's the issue. It is very possible to deduce T here. Compiler
> just isn't trying. The function takes an int. Doesn't take a rocket
> scientist to figure that one out.
I take it your answer is that T must be int. But that's nonsense.
MyAlias maps all types to int. It's not a bijection, you can't turn it
around.
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