Parameters declared as the alias of a template won't accept the arguments of the same type.

[ag0aep6g]

On 02.05.22 22:47, Stanislav Blinov wrote:
> On Monday, 2 May 2022 at 20:16:04 UTC, ag0aep6g wrote:
>> On 02.05.22 21:17, Stanislav Blinov wrote:
>>> On Monday, 2 May 2022 at 16:29:05 UTC, Loara wrote:
>> [...]
>>>> ```d
>>>>     template MyAlias(T){
>>>>       alias MyAlias = int;
>>>>     }
>>>>
>>>>     T simp(T)(MyAlias!T val){
>>>>       return T.init;
>>>>     }
>>>>
>>>>     int main(){
>>>>       simp(3);//Impossible to deduce T
[...]
> That's not my answer. And it is nonsense, because my answer is - what T 
> is irrelevant, MyAlias maps *all* types to int. Therefore `simp` takes 
> an int, which is what the caller is passing.

And what does it return?