pointer escaping return scope bug?

[Dukc]

On Saturday, 19 November 2022 at 15:02:54 UTC, Nick Treleaven 
wrote:
> On Saturday, 19 November 2022 at 14:52:23 UTC, ag0aep6g wrote:
>> That's essentially just a function that returns its pointer 
>> parameter. So the program boils down to this:
>>
>> ```D
>> @safe:
>> int* fp(return scope int* p) { return p; }
>> void main()
>> {
>>     int* p;
>>     {
>>         auto lf = new int;
>>         p = fp(lf);
>>     }
>>     assert(p != null); // address escaped
>> }
>> ```
>>
>> Which is fine, as far as I can tell. `lf` is not `scope`. And 
>> when you pass it through `fp`, the result is still not 
>> `scope`. So escaping it is allowed.
>>
>> You do get an error when you make `lf` `scope` (explicitly or 
>> implicitly). So everything seems to be in order.
>
> OK, so how do I make `lf` implicitly scope?

Have the `int*` inside it to point to a local, or assign another 
`scope int*` to it.