Is "auto t=T();" not the same as "T t;"?
Paul Backus
snarwin at gmail.com
Tue Oct 25 20:12:25 UTC 2022
On Tuesday, 25 October 2022 at 17:54:16 UTC, Salih Dincer wrote:
> On Tuesday, 25 October 2022 at 17:18:35 UTC, Paul Backus wrote:
>> It's not a bug. They're pointing to the exact same instance of
>> `A` in memory:
>
> I don't understand? So I don't understand why it causes
> problems with dynamic arrays! So why is there nothing wrong
> with the static array in the example below?
Static arrays are value types. When you copy a static array, the
copy's data is stored in a separate block of memory from the
original:
```d
int[1] a = [1];
int[1] b = a;
assert(&a[0] !is &b[0]); // different memory
```
Dynamic arrays are reference types. When you copy a dynamic
array, both copies point to the same block of memory:
```d
int[] a = [1];
int[] b = a;
assert(&a[0] is &b[0]); // same memory
```
In order to create a copy of a static array with its own block of
memory, separate from the original, you have to use the built-in
`.dup` method:
```d
int[] a = [1];
int[] b = a.dup;
assert(&a[0] !is &b[0]); // different memory
```
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