bigEndian in std.bitmanip

[Salih Dincer]

Hello,

Why isn't Endian.littleEndian the default setting for read() in 
std.bitmanip?

Okay, we can easily change this if we want (I could use enum LE 
in the example) and I can also be reversed with 
data.retro.array().

```d
void main()
{
   import std.conv : hexString;
   string helloD = hexString!"48656C6C6F204421";
   // compile time converted literal string -ˆ

   import std.string : format;
   auto hexF = helloD.format!"%(%02X%)";

   import std.digest: toHexString;
   auto arr = cast(ubyte[])"Hello D!";

   auto hex = arr.toHexString;
   assert(hex == hexF);

   import std.stdio : writeln;
   hex.writeln(": ", helloD);
// 48656C6C6F204421: Hello D!
   assert(helloD == "Hello D!");

   auto data = arr.readBytes!size_t;
   data.code.writeln(": ", data.bytes);
// 2397076564600448328: Hello D!
}

template readBytes(T, R)
{
   union Bytes
   {
     T code;
     char[T.sizeof] bytes;
   }
   import std.bitmanip;
   enum LE = Endian.littleEndian;

   auto readBytes(ref R data)
   {
    import std.range : retro, array;
    auto reverse = data.retro.array;
    return Bytes(reverse.read!T);
   }
}
```

However, I think it is not compatible with Union. Thanks...

SDB at 79