Mutability issue

[Menjanahary R. R.]

On Saturday, 23 March 2024 at 20:49:14 UTC, Nick Treleaven wrote:
> On Saturday, 23 March 2024 at 19:30:29 UTC, Menjanahary R. R. 
> wrote:
>>     for (T candidate = T(5); candidate * candidate <= n; 
>> candidate += T(6)) {
>
> When T is `const int`, the above code declares and initializes 
> a constant variable:
> ```d
> const int candidate = const int(5);
> ```
>
> Then, at the end of each loop iteration, it does:
> ```d
> candidate += const int(6);
> ```
>
> So you are trying to modify a constant. Constants can only be 
> initialized, never assigned.
>
>>     T candidate = (n % T(2) == T(0)) ? n + T(1) : n + T(2); // 
>> Start from next Odd
>>
>>     for (;; candidate += T(2)) { // Skip even
>
> Same here, you declare a constant then try to assign to it at 
> the end of each loop iteration.

Thanks for your prompt answer.