std.string.format

[Frits van Bommel]

Egor Starostin wrote:
> I have a couple of issues with std.string.format.
> 
> 1. why
> writefln(format("%%1.%df",2));
> produces 'Error: std.format'

Because the format function returns "%1.2f", so writefln expects an 
extra floating-point argument after that string.
What you may be after is
	writefln("%s", format("%%1.%df",2));

> but
> writefln(format(format("%%1.%df",2),1.0));
> works fine?

Here the outer format call returns "1.00" which is a regular string, so 
writefln() doesn't have a problem with it.


If you're passing a string to writefln() that contains % signs you want 
to be sent to the console, either make sure they're properly quoted 
(i.e. %% instead of %) or pass a format string that expects a string 
before it (e.g. "%s").
If you don't want them to be sent to the console but want them to be 
interpreted and substituted, make sure you supply the correct number 
(and type) of arguments...