Function pointer argument to function template

[Daniel Keep]

Tom S wrote:
> Hey there :)
> 
> I came up with this:
> 
> ----
> 
> import std.stdio;
> 
> template Deref(T) {
>         alias typeof(*T) Deref;
> }
> 
> template RetType(T) {
>         static if (is(Deref!(T) U == function)) {
>                 alias U RetType;
>         } else static assert (false);
> }
> 
> template Bar(T, U=RetType!(T)) {
>         U Bar(T t) {
>                 writefln(typeid(U));
> 
>                 // do something :P
>                 return U.init;
>         }
> }
> 
> 
> cfloat func(int a, float b) {
>         return 1.f + 0i;
> }
> 
> 
> void main() {
>         writefln(Bar(&func));
> }
> 
> 
> -- 
> Tomasz Stachowiak  /+ a.k.a. h3r3tic +/

Wow.  That's... so much nicer than mine.  I'm not even going to post my
comparatively hideous solution :p

May as well ask this: do you know a simple way to infer both the number
and type of a function's arguments?  I have a set of templates that can
do this, but they're somewhat ugly.

	-- Daniel

-- 
Unlike Knuth, I have neither proven or tried the above; it may not even
make sense.

v2sw5+8Yhw5ln4+5pr6OFPma8u6+7Lw4Tm6+7l6+7D
i28a2Xs3MSr2e4/6+7t4TNSMb6HTOp5en5g6RAHCP  http://hackerkey.com/