Xinok wrote:
> To accomplish what alias expressions could do, you would have to write all of this:
> template mul(V...){
> const typeof(V[0] * V[1]) mul = V[0] * V[1];
> }
>
> Compared to:
> alias (a*b) mul(a, b);
That typeof(...) is redundant. Remove that and it should default to
automatic type deduction, which would do exactly the same.