iterators again

[Walter Bright]

Bruno Medeiros wrote:
> I know I can change the members of a final class, if I use the class 
> reference directly (like "foo.membervar = 42"). However it seems that 
> with that design, if one uses (*(&foo)) one won't be able to change the 
> members of (*(&foo)) , as in "(*(&foo)).membervar = 42", even tough foo 
> is conceptually the same as (*(&foo)). I was just checking if you 
> recognized that this happens.

Yes.