opStarAssign?

[0ffh]

Frits van Bommel wrote:
> 0ffh wrote:
>> I'd guess that cases where both "x=y;" and "*x=y;" make sense are 
>> rare. So overloading opAssign for the parameter type might be quite 
>> sufficient.
> 
> Even if they're rare, they *do* exist (for example, a variant type that 
> can store both normal types and pointers).

You mean like:

   int y=0;
   Variant x=&y;
   *x=3;
   printf("%i\n",y); // prints 3

Wouldn't this be quite sufficient, without the need to "*x=":

   int y=0;
   Variant x=&y;
   int* z;z=x;
   *z=3;
   printf("%i\n",y); // prints 3

Variant is obviously a very special case. I wonder if we really need
this... I think I see quite some potential for serious shootings of
feet here... okay, I'm all for it now! =)

regards, frank