The new ?? and ??? operators

[Janice Caron]

On 9/23/07, Arlen Albert Keshabyan <arlen.albert at gmail.com> wrote:
> Consider this:
>
> int v = 15;
> int v2 = 30;
>
> int a = v > 20 ??? v = 17 ??? v2 < 25 ??? 5;
>
> in this case 'a' evaluates to 5 because none of the conditions evaluate to true except the last one. if you remove the last condition (??? 5) then 'a' stays 0 in this case.
>
> If v2 = 23 then 'a' evaluates to 23;
> If v = 27 then 'a' evaluates to 27;
>
> etc.
>
> It means that it takes a sequential rvalue, tests it against a condition and if the condition evaluates to true then it assigns that rvalue to lvalue. It does not mean you are restricted to boolean values only.

I assume you meant v == 17, not v = 17 there, since v = 17 would be an
assignment. In any case

int a = v > 20 ??? v == 17 ??? v2 < 25 ??? 5;

Looks to me the same as

int a = v > 20 ? v : (v == 17 ? v : (v2 < 25 ? v2 : 5));

Could be just me, but the latter seems readable and more expressive.