The new ?? and ??? operators

[Arlen Albert Keshabyan]

Stewart Gordon Wrote:

> "Arlen Albert Keshabyan" <arlen.albert at gmail.com> wrote in message 
> news:fd6ee0$nd4$1 at digitalmars.com...
> > Stewart Gordon Wrote:
> >> "Arlen Albert Keshabyan" <arlen.albert at gmail.com> wrote in message
> >> news:fd68lm$f4r$1 at digitalmars.com...
> >> > A a = APointer1 ?? APointer2 ?? APointer3;
> >> >
> >> > the line above is equal to the line below:
> >> >
> >> > A a = APointer1 != null ??? APointer2 != null ??? APointer3 != null ???
> >> > null;
> >>
> >> Not by the way you specified it.  The first would assign to a an actual
> >> object reference; the second would try to assign a boolean value.
> <snip>
> > No. The code lines do the same thing anyway.
> 
> Which same thing - evaluating to a boolean or evaluating to an object 
> reference?  Are you going to supply a corrected version of your proposal?
> 
> Stewart.
> 
> -- 
> My e-mail address is valid but not my primary mailbox.  Please keep replies 
> on the 'group where everybody may benefit. 
> 


It evaluates to an object reference.