Why Strings as Classes?

[Sergey Gromov]

Robert Fraser <fraserofthenight at gmail.com> wrote:
> First, a hash access is already time unbounded. hash["hello"] where 
> "hello" is not already in the hash will create a hash entry for hello. 
> This requires heap allocation, which can take arbitrarily long. So 
> having unbounded opIndex is in the language already!

Hash's opIndex() throws an ArrayBoundsError if given an unknown key. 
It's opIndexAssign() which allocates.

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SnakE