transporting qualifier from parameter to the return value
Walter Bright
newshound1 at digitalmars.com
Tue Dec 15 22:06:58 PST 2009
Andrei Alexandrescu wrote:
> Any thoughts would be appreciated.
The more I think about this, the more I think it cannot work unless
inout is elevated to be a full type constructor, just like const,
immutable, and shared are.
For example:
inout(char[]) foo(inout char[] p)
{
char[] s = p;
return s; // ulp, doesn't work
const char[] s = p;
return s; // ulp, doesn't work
immutable char[] s = p;
return s; // ulp, doesn't work
auto s = p;
return s; // ulp, doesn't work
}
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