array literal element types

[Steven Schveighoffer]

On Fri, 13 Nov 2009 07:34:14 -0500, Steven Schveighoffer  
<schveiguy at yahoo.com> wrote:

> On Thu, 12 Nov 2009 20:16:40 -0500, Robert Jacques <sandford at jhu.edu>  
> wrote:
>
>> On Thu, 12 Nov 2009 16:42:45 -0500, Walter Bright  
>> <newshound1 at digitalmars.com> wrote:
>>
>>> Currently, the type is determined by the type of the first element and  
>>> the rest are implicitly cast to it.
>>>
>>> I propose changing it to being the type produced by applying the ?:  
>>> logic repeatedly to all the elements.
>>
>> Given how numeric literals currently work:
>> vote--
>>
>> for example currently:
>> float[] = [1.0f, 2.5, 5.6, 0.8].dup;
>>
>> under the proposal
>> float[] = [1.0f, 2.5f, 5.6f, 0.8f].dup;
>>
>
> How about if a cast is sticky?  That is, the last detected cast inside  
> an array literal is applied to subsequent elements that do not have a  
> cast:
>
> [cast(float)1.0, 2.5, 5.6, 0.8]; // equivalent to [1.0f, 2.5f, 5.6f,  
> 0.8f] => float[]
>
> [cast(float)1.0, 2.5, cast(double)5.6, 0.8]; // equivalent to [1.0f,  
> 2.5f, 5.6, 0.8] => double[]

Nevermind...  I guess this already works:

cast(float[])[1.0, 2.5, 5.6, 0.8]

I don't see the OP's point as being an issue in light of this.

-Steve