D array expansion and non-deterministic re-allocation

Tim Matthews tim.matthews7 at gmail.com
Sun Nov 15 18:05:07 PST 2009


Bartosz Milewski wrote:
> I read Andrei's chapter on arrays and there's one thing that concerns me. When a slice is extended, the decision to re-allocate, and therefore to cut its connection to other slices, is non-deterministic. How does that influence program testing and can it be exploited to attack a buggy system?
> 
> Here's a piece of code I came up with--it's not realistic but it describes a certain class of scenarios:
> 
> void f(byte[] code)
> {
>     doSomeChecks(code);
>     execute(code);
> }
> 
> void doSomeChecks(byte[] a)
> {
>>   // to avoid special-casing empty arrays
>   a.length += 1; // extension
>>   // get byte b (or a whole bunch) from somewhere
>    a[0] = b; // write
>>   // check what happens when a[0] = b
> }
> 
> Of course this code is incorrect because doSomeChecks assumes that it holds a unique array, and the caller failed to make a copy before sending it to doSomeChecks. Bad bad programmer!
> 
> However imagine this scenario: Under testing conditions, the array extension just happens to always cause reallocation, so the write is NOT visible in the calling routine. All tests pass with flying colors. But since the re-allocation is, by language definition, non-deterministic, it might happen that, after the code has been deployed, the re-allocation stopped happening, say, on Sundays. If a hacker learns about that, he may be able to inject malicious code or data into the program. 
> 
> In this case the non-determinism built into the language helped camouflage a serious bug. Should we, or shouldn't we, worry about it in practice?

Isn't the new kind of arrays created to fix this already? See T[new].

PS: Are you still working on D's concurrency?



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