std.algorithm move() struct emptying

[Torarin]

Yes, you are right!
Looking at the assembly, T.init creates a struct on the stack.

2010/8/29 Stanislav Blinov <stanislav.blinov at gmail.com>
>
> Torarin wrote:
>>
>> Hi,
>> in std.algorithm move(), this is the operation used to set the source of a struct move to .init:
>>
>>  static T empty;
>>  memcpy(&source, &empty, T.sizeof);
>>
>> Is there any particular reason why the more compact &T.init is not used?
>>
>
> I may be wrong, but it seems that in this case T.init will yield a temporary, while static T empty is 'always' there.
>
> Consider:
>
> struct S {}
>
> void main()
> {
>        writefln("%x", &S.init); // prints one value
>        writefln("%x", &S.init); // prints another value
>
>        static S s;
>
>        writefln("%x", &s); // prints one value
>        writefln("%x", &s); // prints the same value
> }