Destructors, const structs, and opEquals

[Andrei Alexandrescu]

On 12/4/10 6:50 AM, so wrote:
>> I'm 99.99% certain that it's perfectly legal to pass a temporary to a
>> function
>> that takes a const T& and that it's in the standard
>
> Oh that is right, but both are different things.
>
> Say, when you have:
>
> T fun() {...}
> void bar(const T&) {...}
>
> bar(fun()) // 1. this is perfectly legal.
> const T& a = fun(); // 2. not legal, but still you can do it on some
> compilers.
>
> What Don's example is all about as far as i can tell is that D can't do
> the first one, somehow.

Second line is legal too. Petru Marginean and I use it to good effect in 
our ScopeGuard idiom (a precursor to D's scope guards).

http://www.drdobbs.com/184403758

Andrei