Why Ruby?

Andrej Mitrovic andrej.mitrovich at gmail.com
Sun Dec 19 15:18:20 PST 2010


int[] a = [ 1, 2, 3 ];
string[] b = [ "a", "b", "c" ];
sort!("a[0] > b[0]")(zip(a, b));

or

int[] a = [ 1, 2, 3 ];
string[] b = [ "a", "b", "c" ];
sort!(@[0] > @[0])(zip(a, b));

--

auto var = sequence!("a[1] + n-1 + a[0]")(1, 2);

or

auto var = sequence!(@1[1] + n-1 + @1[0])(1, 2);


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