OT: Linux shell validate-all-command-before-executing-anything behavior?

BCS none at anon.com
Sun Feb 14 22:54:07 PST 2010


Hello Nick,

> I'm trying to make a trivial shell script (as portable as possible) to
> build an executable and then run it. Basically something like this:
> 
> -----------------------------
> #!/bin/sh
> # Assume that foo is a natively-compiled program,
> # not a script or anything, and gets placed in './bin'
> make foo
> ./bin/foo
> -----------------------------
> But, when I try to run that, it complains that './bin/foo' doesn't
> exist and exits *before* it ever actually invokes 'make foo' (just an
> example) which is exactly what *creates* './bin/foo' in the first
> place. Can anyone provide any insight/perspective/background-info to
> this apparent "validate all commands in the script against the
> filesystem before actually running the script" behavior?
> 
> I apologize for bringing something so enormously off-topic here, but
> the closest thing I'm getting to an intelligent answer over at the
> Ubuntu Forums is "It's 'make', not 'make foo', and if that doesn't
> work, what are you trying to build?" I'm a bit fearful for my sanity
> at the thought of bringing the same question to yet other forum that I
> don't already know for certain to be populated with people who
> actually know what they're talking about. So I just came straight here
> with it instead. I *know* that people here are intelligent.
> 

I'd check to make sure that running "make foo" works because I don't think 
that bash does the checking you seem to be seeing.

Also ask the question here: http://serverfault.com/ or here http://superuser.com

Both sites tend to give good and fast results.

--
<IXOYE><





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