Should scope(exit) be valid outside of a scope?

Don nospam at
Tue May 11 13:18:29 PDT 2010

Consider the following code
import std.stdio;

void foo(bool x)
    if (x)
       scope(exit) writeln("exiting");
If the scope(exit) isn't in a compound statement (ie, if it isn't inside 
{}), the 'scope' applies only to the statement itself, so that's 
identical to:
    if (x) writeln("exiting");
which is useless and probably not what was intended.
Ditto for scope(success).

Currently the scope(exit) doesn't get executed at all (it's bugzilla 
1894). But I suspect that any such use of scope guards is a bug.
Can we just make it illegal?

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