Inheriting from an interface twice

[Simen kjaeraas]

Trass3r <un at known.com> wrote:

>> void main()
>> {
>> 	Baz baz = new Baz();
>> 	Bar bar = baz;
>> 	
>> 	Foo foo1 = bar;
>> 	Foo foo2 = baz;
>> 	
>> 	assert(foo1 is foo2);
>> }
>>
>>
>> foo1 and foo2 have the same type and point to the same object. Yet they  
>> have different addresses. Is it a bug, or a feature?
>
> Looks fine?! Isn't foo1 == foo2 what you want?

He mentioned that the code asserts. I say this is fishy, but I don't know
if it should assert or not.

-- 
Simen