Why D const is annoying
Timon Gehr
timon.gehr at gmx.ch
Tue Dec 13 02:45:44 PST 2011
On 12/13/2011 01:58 AM, Jesse Phillips wrote:
> On Sun, 11 Dec 2011 19:40:42 +0100
> Mafi<mafi at example.org> wrote:
>
>> void f(ref const(int)* a, const(int)* b) {a = b; }
>> void main() {
>> immutable(int)* a;
>> auto b = (new int[](5)).ptr;
>> f(a, b);
>> //if this compiles I have just assigned a mutable pointer
>> //to an immutable one
>> }
>>
>> With the above definition using inout, such a call would be
>> disallowed.
>
> Just gave this code a try:
>
> void f(ref const(int)* a, const(int)* b) {a = b; }
> void main() {
> const(int)* a;
> immutable(int)* b;
> auto c = (new int[](5)).ptr;
> f(a, c);
> f(b, c); //test.d(7): Error: cast(const(int)*)b is not an lvalue
> }
Interesting. That is another bug that masks the one you were trying to
exploit. :o) Consider:
void f(const ref int* a) { }
void main() {
immutable(int)* a;
f(a); // same error, but should compile
}
Anyway this does the same bad stuff as your example was trying to do and
currently compiles:
void f(const(int)** a, const(int)* b) {*a = b; }
void main() {
const(int)* a;
immutable(int)* b;
auto c = (new int[](5)).ptr;
f(&a, c);
f(&b, c); // now goes through
}
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