Uniform call syntax for implicit this.

Michel Fortin michel.fortin at michelf.com
Thu Feb 3 11:15:11 PST 2011


On 2011-02-03 13:42:30 -0500, Jonathan M Davis <jmdavisProg at gmx.com> said:

> On Thursday, February 03, 2011 09:54:44 Michel Fortin wrote:
>> On 2011-02-03 12:43:12 -0500, Daniel Gibson <metalcaedes at gmail.com> said:
>>> Am 03.02.2011 15:57, schrieb Michel Fortin:
>>>> On 2011-02-02 23:48:15 -0500, %u <dflgkd at sgjds.com> said:
>>>>> When implemented, will uniform call syntax work for the "this"
>>>>> object even if not specified?
>>>>> 
>>>>> For example, will foo() get called in the following example?
>>>>> 
>>>>> void foo(A a, int b) {}
>>>>> 
>>>>> class A {
>>>>> void test() {
>>>>> this.foo(10);
>>>>> foo(10);
>>>>> }
>>>>> }
>>>> 
>>>> I think it should work.
>>> 
>>> I think foo(10) should *not* be equivalent to foo(this, 10).
>> 
>> Personally, I'm not sure whether the uniform call syntax will be this
>> much useful or not, but if it gets implemented I think foo(10) should
>> be equivalent to foo(this, 10) in the case above. That said, it should
>> not be ambiguous: if there is a member function foo and a global
>> function foo and both matches the call, it's ambiguous and it should be
>> an error.
>> 
>> Can this work in practice? We probably won't know until we have an
>> implementation to play with.
> 
> Except that if you have both a member function foo and a free function foo, how
> can you tell the compiler which to use?

Indeed, that's a problem. The solution is to sidestep the problem. :-)

We just have to disallow declaring a module-level function and a 
class-level function with the same name and the same parameter types 
(including 'this' in the parameters).

	void foo(A a, int i);

	class A {
		void foo(int i); // error, same as foo(A, int)
	}

If the module-level function is in a different module, then you can use 
the module name to disambiguate if necessary. If they're in the same 
module, the compiler catches the error during semantic analysis of the 
module.

I'm not too sure how disruptive this change would be to existing code. 
I'm under the impression that this situation is rare, but I can't say 
for sure.


-- 
Michel Fortin
michel.fortin at michelf.com
http://michelf.com/



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