Why does this work?

[Vladimir Panteleev]

On Fri, 18 Feb 2011 07:06:26 +0200, Jason House  
<jason.james.house at gmail.com> wrote:

> I would have expected bar to equal 2 since foo would be default  
> initialized to 2. I'm going to guess that the there's some kind of  
> optimization that only assigns to foo once and isn't noticing that bar  
> depends on it.

Nope:

int foo;
enum bar = foo+2;

void main()
{
	foo = 7;
	assert(bar == 9);
	foo++;
	assert(bar == 10);
}


> You should probably post that in bugzilla.

And complain about basically having expression macros?!

-- 
Best regards,
  Vladimir                            mailto:vladimir at thecybershadow.net