Pure higher order functions

bearophile bearophileHUGS at lycos.com
Thu Jul 7 04:34:37 PDT 2011


With the latest beta update this compiles:


@property bool empty(T)(in T[] a) pure nothrow {
    return !a.length;
}

@property ref T front(T)(T[] a) pure nothrow {
    assert(a.length);
    return a[0];
}

void popFront(A)(ref A a) pure nothrow {
    assert(a.length);
    a = a[1 .. $];
}

struct Map(alias fun, R) {
    R _input;

    this(R input) nothrow pure {
        _input = input;
    }

    @property bool empty() nothrow const pure {
        return _input.empty;
    }

    @property auto ref front() nothrow const pure {
        return fun(_input.front);
    }

    void popFront() nothrow pure {
        _input.popFront();
    }
}

template map(alias fun) {
    auto pure map(R)(R range) {
        return Map!(fun, R)(range);
    }
}

int sqr(int x) pure nothrow { return x * x; }

pure nothrow int foo(int n) {
    int total;
    foreach (x; map!(sqr)([1, 2, 3, 4]))
        total += x;
    return total;
}

void main() {
    assert(foo(10) == 30);
}


But I have had to write, this I don't know why:
auto pure map(R)(R range) {

And despite Map is a template, its methods aren't pure, so I have had to write them with pure:
@property bool empty() nothrow const pure {

So I think currently map() can't be pure.
I think we need the notion of pure structs/classes (instances).

Bye,
bearophile


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