nan or -nan?

[Iain Buclaw]

On 17 November 2011 23:57, bearophile <bearophileHUGS at lycos.com> wrote:
> Iain Buclaw:
>
>> This behaviour may be due to the libraries rather than the compiler.
>
> In any case there is a bug to be found an fixed.
>

When I said libraries, I meant system libraries - ie: glibc. I seem to
recall it being added a few years back.  If you are on an older
system, or Windows, you may not see the signedness at all.



-- 
Iain Buclaw

*(p < e ? p++ : p) = (c & 0x0f) + '0';