extern(C++) and shared

[deadalnix]

Le 27/11/2011 13:17, Jude Young a écrit :
> On Sun 27 Nov 2011 05:54:27 AM CST, deadalnix wrote:
>> Le 27/11/2011 12:02, Jacob Carlborg a écrit :
>>> On 2011-11-27 01:20, deadalnix wrote:
>>>> I have this function :
>>>> extern(C++) void* __dsfml_start_thread(EntryPoint entryPoint, void*
>>>> userData);
>>>>
>>>> If EntryPoint is defined as follow :
>>>> alias extern(C++) void* function(void*) EntryPoint;
>>>>
>>>> The function mangle in _Z20__dsfml_start_threadPFPvS_ES_
>>>>
>>>> if alias extern(C++) void* function(shared void*) EntryPoint;
>>>> _Z20__dsfml_start_threadPFPvPvES_
>>>>
>>>> Both demangle using c++filt in __dsfml_start_thread(void* (*)(void*),
>>>> void*), which is what is expected.
>>>>
>>>> But the definition without shared will be the only one to link
>>>> successfully.
>>>>
>>>> Is the mangling of shared types is consistent in C++ ? shared doesn't
>>>> exists in C++, so I guess we should expect the same mangling in both
>>>> cases. Unless it exists some magic on the C++ side that I'm not aware
>>>> of ?
>>>
>>> Have you tried with __gshared instead?
>>>
>>
>> It doesn't compile at all with __gshared. I have the following error :
>> basic type expected, not __gshared
>>
> extern (C++)
> {
> __gshared type function(blah) blah;
> alias foo bar;?
> }
> that doesn't work?

That does work. But isn't what is failing here.