NULL indicator in Variant

Steve Teale steve.teale at britseyeview.com
Thu Oct 27 09:58:57 PDT 2011


On Thu, 27 Oct 2011 16:16:26 +0200, Alex Rønne Petersen wrote:

> On 27-10-2011 15:50, Steve Teale wrote:
>>>
>>> Surely Variant.init should do the trick?
>>
>> Dmitry,
>>
>> Are you talking about the new std.variant - I don't see 'init'
>> currently.
>>
>> Steve
> 
> He is probably referring to the 'init' property on the *type*, i.e.
> int.init and so on.
> 
> - Alex

Same catch 22. In order to have an init property, the Variant would have 
to have been set to some type, at which point hasValue() would say yes.

Steve


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