Predefined 'release' version?

[Ali Çehreli]

On 04/20/2012 11:14 AM, Xinok wrote:
> On Friday, 20 April 2012 at 17:43:49 UTC, Ali Çehreli wrote:
>> On 04/20/2012 10:24 AM, Bernard Helyer wrote:
>>> On Friday, 20 April 2012 at 15:26:24 UTC, H. S. Teoh wrote:
>>>> I just discovered to my dismay that dmd does not define version=release
>>>> when compiling in -release mode. What's the reason for this?
>>>>
>>>> I have some code that uses ctRegex, which slows down compilation
>>>> significantly due to heavy amounts of CTFE, but which speeds up the
>>>> final executable. I'd like to version this code and use regular regex()
>>>> for non-release builds, and switch to ctRegex for release builds. Yes I
>>>> can just pass in a version on the commandline, but it'd be nice if it
>>>> could be triggered automatically by -release.
>>>>
>>>>
>>>> T
>>>
>>> debug {
>>> // blah
>>> } else {
>>> // fast blah
>>> }
>>>
>>
>> debug blocks are activated when -debug switch is explicitly specified,
>> not when -release is not specified. :)
>>
>> Ali
>
> The code in "else" will be used in release builds.


Define "release build". :) Despite appearances -debug and -release are 
othogonal.

debug blocks are activated by the -debug switch. -release is unrelated 
to -debug. You can use both switches:

   http://dlang.org/dmd-linux.html

Ali