Modulo Bug?

[David]

> Besides, modulo of unsigned integers would
> still work the same, so you could just use that when you cared about the
> difference in performance. So the only situation where you couldn't
> avoid performance penalty would be when you needed to calculate modulo
> of signed integers and you actually wanted the current behavior. I think
> that is a pretty rare situtation.

My implementation of py_mod:

int py_mod(int a, int b) {
     return cast(uint)a % b;
}

So a simple cast from signed to unsigned does exactly what I need 
(Prf_Jakob showed me that in IRC)

How much does a cast cost? I mean is that even an extra asm instruction?

>> Why hasn't the Python-modulo been made the default back when D was
>> designed?
>
> Probably because this is one of the design goals of D: Where D code
> looks the same as C code, have it either behave the same or issue an error.


Unfortunatly.