Function pointers/delegates default args were stealth removed?

[Daniel Murphy]

"Jonathan M Davis" <jmdavisProg at gmx.com> wrote in message 
news:mailman.1446.1346070222.31962.digitalmars-d at puremagic.com...
>
> Default arguments just do not make sense with function pointers, because 
> they
> don't follow the function pointer, because it's a _pointer_ and has no
> knowledge of what it's pointing to. It's only at the declaration point of 
> the
> function that the default argument exists, and that has _nothing_ to do 
> with
> the function pointer. You might as well ask a reference of type Object 
> what
> the arguments used to construct the derived class that it actually refers 
> to
> were as expect a function pointer to have any clue about default arguments 
> to
> the function that it points to.
>
> - Jonathan M Davis

Yes, this.  I looked into fixing issue 3866 earlier this year, and Kenji's 
list sounds very familiar.

It comes down to - function pointers are not function declarations and 
therefore can't do everything function declarations do, such as overloading 
and default arguments.  This is the price of being able to reassign them.

Yes it is possible to make them work the way Manu has been using them, but 
the solution is messy and I seriously doubt it's worth it.  I agree with 
everything Andrei has said about this.

I don't consider putting default arguments back in the type a valid approach 
because of the reason above, so that leaves giving function pointer 
variables the ability to have default arguments.  This seems to me like a 
really dumb corner case with the same problems.