Is there any reason why arithmetic operation on shorts and bytes return int?
d coder
dlang.coder at gmail.com
Tue Dec 11 04:29:42 PST 2012
For some more clarity, when I compile the following code:
void main() {
import std.stdio;
byte a;
byte b;
byte c = a + b;
}
I get error:
test.d(6): Error: cannot implicitly convert expression (cast(int)a +
cast(int)b) of type int to byte
Why is D trying to convert bytes and shorts to integers before applying any
arithmetic operator?
Regards
- Puneet
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