Is there any reason why arithmetic operation on shorts and bytes return int?

[Simen Kjaeraas]

On 2012-09-12 00:12, js.mdnq <js_adddot+mdng at gmail.com> wrote:

> struct bbyte {
> byte value;
> ...
> }
>
> bbyte a; bbyte b;
>
> b = a + b; // uses bbyte's operators and casts to do the computation and  
> assignment but then returns a bbyte instead of an int.
>
> You should have no problems implicitly converting bbyte to built in  
> types or built in types to bbyte.

Not entirely true. Converting from bbyte to built-in works, but these
are to my knowledge currently impossible:

void foo(bbyte b);
byte b;

foo(b); // No conversion.


bbyte bar( ) {
     byte b;
     return b;
}


-- 
Simen