Output to console from DerivedThread class strange

Oliver Puerto saxo123 at gmx.de
Tue Feb 7 14:28:30 PST 2012


I have a question concerning threading. I use Visual Studio with the Visual-D plugin. The problem is somehow that when executing the code below "Derived thread running." is displayed 3 times on the console but not before "return 0" is reached. Then "Derived thread running." is displayed 3x all of a sudden, but not each one by one after each other. This looks a bit strange to me.

When I unquote the Thread.sleeps after every d?.start() "Derived thread running." is displayed immediately on the console when stepping over Thread.sleep with the debugger. When stepping over d*.start() still nothing happens regardless how much time I wait in the debugger till I jump to the next line. I can't make really head or tail of this. I would expect "Derived thread running." to appear on the console somewhen after d?.start() was executed. Thereafter I could do an additional Thread.sleep if I wanted to. But this would not be necessary for any "Derived thread running." message to be displayed on the console. 

I believe there is something with the debugger I don't understand or don't realize. Any suggestions/ideas?

Thank you, Oliver Plow

import std.stdio, core.thread;

import DerivedThread;

int main(string[] argv)
    DerivedThread dt1 = new DerivedThread();	
    // Thread.sleep(dur!("seconds")( 1 ));
    DerivedThread dt2 = new DerivedThread();	
    // Thread.sleep(dur!("seconds")( 1 ));
    DerivedThread dt3 = new DerivedThread();	
    // Thread.sleep(dur!("seconds")( 1 ));
    Thread.sleep(dur!("seconds")( 4 ));    
    return 0;

------------------ DerivedThread.d ------------------

import std.stdio, core.thread;

class DerivedThread : Thread { 
	this() { 
		super( &run ); 

private : 
	void run() { 
		writeln("Derived thread running."); 
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