Specialization - Major hole in the spec?

[Peter Alexander]

On 5/01/12 1:53 AM, Timon Gehr wrote:
> On 01/05/2012 03:01 AM, Peter Alexander wrote:
>> On 5/01/12 1:19 AM, Timon Gehr wrote:
>>>> foo!int(0); // 1
>>>
>>> Matches both 1 and 2. 2 is strictly more specialized, therefore 2 is
>>> chosen. Mistake on your side.
>>
>> It chooses 1 because I have specified T to be int so 2 can't possibly
>> match.
>>
>
> Test it. int implicitly converts to float, therefore it matches 2.
>
> void foo(T)(T t){writeln(1);}
> void foo(T:float)(int t){writeln(2);}
> void main(){foo!int(0);} // prints "2"

Strange, I could have sworn that printed 1 when I tried it the first time.

In any case, it is surely a bug. I have *explicitly* specified that T 
must be int, yet it has called a version with T == float.