Calling an alias for a Class method in another scope

Max Samukha maxsamukha at
Sat Jun 2 10:33:02 PDT 2012

On Friday, 1 June 2012 at 14:33:59 UTC, d coder wrote:
> Steve
> One small thing. As you said I might declare a delegate in an 
> alternate
> fashion that is by saying "void delegate() dg;".
> But would it be possible to rewrite the following declaration 
> in a way that
> avoids naming foo explicitly. I would just have an alias for 
> foo. I am
> asking this to cover the cases where foo might have a list of 
> arguments and
> I want to create a delegate with the same list of arguments.
> typeof(& dg;
> Regards
> - Puneet

The language/standard library do not provide a straightforward
way of constructing a delegate type from a corresponding function
(of function pointer) type, so you will have to go hacky. It is
easiest to use std.functional.toDelegate (don't ask why it is in

import std.functional : toDelegate;

auto ref call(alias fn, T, A...)(T t, auto ref A args)
      typeof(toDelegate(&fn)) dg;
      dg.ptr = cast(void*)t;
      dg.funcptr = &fn;
      return dg(args);

At the moment, the ref-ness of the return type is not determined
correctly because of a compiler bug. Otherwise, that works mostly

Note, that the delegate approach comes with performance penalty,
which dmd cannot currently optimize out. So it is slower than a
direct call.

In a parallel reality D would have a separate kind of (pointers
to) functions that take a context pointer. Something like

extern(DWithContext) function(...)

Then such functions/function pointers could be made callable
directly with the context pointer as the first argument. Also, a
delegate's funcptr would be typed correctly.

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