How to break const

[Mehrdad]

On Monday, 18 June 2012 at 14:55:42 UTC, Mehrdad wrote:
> Identical calls giving identical results? What?
>
>
> import std.stdio;
> struct S
> {
>          this(int a)
>          {
>                  this.a = a;
>                  this.increment = { return this.a++; };
>          }
>          int a;
>          int delegate() pure increment;
>          auto oops() const { return this.increment(); }
> }
> void main()
> {
>          auto c = immutable(S)(0);
>          writeln(c.oops()); // 0
>          writeln(c.oops()); // 1
>          writeln(c.oops()); // 2
>          writeln(c.oops()); // 3
>          writeln(c.oops()); // 4
>          writeln(c.oops()); // 5
> }



Heck, make that all @safe pure nothrow:

          int delegate() pure @safe nothrow increment;
          auto oops() pure const @safe nothrow { return 
this.increment(); }