standard ranges

[Gor Gyolchanyan]

On Wed, Jun 27, 2012 at 7:49 PM, Jonathan M Davis <jmdavisProg at gmx.com>wrote:

> On Wednesday, June 27, 2012 19:47:41 Gor Gyolchanyan wrote:
> > On Wed, Jun 27, 2012 at 7:41 PM, Jonathan M Davis
> <jmdavisProg at gmx.com>wrote:
> > > On Wednesday, June 27, 2012 17:58:46 Gor Gyolchanyan wrote:
> > > > I tested it out and the string literal without qualifiers counts as a
> > > > dstring.
> > >
> > > That depends entirely on what you assign it to.
> > > writeln(typeof("hello").stringof) prints string, not dstring. So, the
> > > literal
> > > by itself is a string by default.
> > >
> > > - Jonathan M Davis
> >
> > this is weird. I wrote a function, which transforms anything, which
> > qualifies as isForwardRange into an implementation of ForwardRange. And
> the
> > type inference of that function produced a ForwardRangeImpl!dchar when I
> > passed it a string literal.
> >
> > Although string and wstring also qualify as a forward range.
>
> _All_ strings are considered to be ranges of dchar. That's why string and
> wstring are not random access ranges and hasLength is false for them.
>
> - Jonathan M Davis
>

So why is the type of a string literal _string_ by default? Isn't it
confusing when dealing with ranges?

-- 
Bye,
Gor Gyolchanyan.
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