Multiple return values...

[Andrei Alexandrescu]

On 3/13/12 1:20 PM, Manu wrote:
> What value does it add over Kenji's change? Is this because Kenji's
> change is unable to perform direct to existing variables?

Yes.

> My understanding from early in the thread was that Kenji's change hides
> the returned tuple, and performs a convenient unpack. How can you
> perform a scatter if the tuple instance is no longer visible?

If I understand you correctly, you just say fun().scatter(v1, v2, v3).


Andrei