Multiple return values...

[Manu]

On 13 March 2012 21:40, Andrei Alexandrescu
<SeeWebsiteForEmail at erdani.org>wrote:

> On 3/13/12 1:20 PM, Manu wrote:
>
>> What value does it add over Kenji's change? Is this because Kenji's
>> change is unable to perform direct to existing variables?
>>
>
> Yes.
>
>
>  My understanding from early in the thread was that Kenji's change hides
>> the returned tuple, and performs a convenient unpack. How can you
>> perform a scatter if the tuple instance is no longer visible?
>>
>
> If I understand you correctly, you just say fun().scatter(v1, v2, v3).


Ah okay, I see.
And you think that's more readable and intuitive than: (v1, v2, v3) =
fun(); ?
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