Properties don't behave like variables?

[Steven Schveighoffer]

On Mon, 07 May 2012 15:35:35 -0400, Jacob Carlborg <doob at me.com> wrote:

> On 2012-05-07 14:43, Steven Schveighoffer wrote:
>
>> It's like this in C#.
>>
>> I can't decide whether I like it better in D or C#. Clearly the compiler
>> lowering of foo |= 2 to foo = foo | 2 would be benficial in terms of
>> less code to write.
>>
>> But I also like having control over how properties can implement
>> operators. For example, the above is two function calls, but it may be
>> easier/more efficient written as one. The issue is, how do you do that?
>>
>> The current definition syntax doesn't lend itself well to extension...
>>
>> -Steve
>
> If an operator is overloaded use that single function, otherwise do a  
> rewirte.

How do you overload the operator for a property?  For example:

struct S
{
    int x;
}

struct T
{
    private int _x;
    @property S s() { return S(_x);}
    @property void s(S news) { _x = newS.x; }
}

How do I define T.s |= 5 ???

I realize we could define opBinary("|") on S, and depend on the rewrite,  
but I'd rather do it in one operation.

-Steve