scope(exit) without exception handling?

[Jonathan M Davis]

On Wednesday, May 16, 2012 05:54:04 Mehrdad wrote:
> I'm writing some (low-level) code with no exception handling
> available whatsoever... either the code runs, or it doesn't.
> 
> Is there any way for me to use scope(exit) (or perhaps a
> destructor, like RAII) to mean, "Execute this block of code for
> me when the block is exited, will ya?", *without* introducing
> dependencies on exception handling?

scope(exit) stuff;
otherStuff;

is lowered to something like

try
{
    otherStuff;
}
finally
{
    stuff;
}

So, you can use scope(exit) if the above code is acceptable for whatever 
you're doing. Otherwise, no, you can't.

Destructors should work regardless of what you're doing with exceptions 
though, so I would expect RAII to work.

- Jonathan M Davis