function overload on full signature?

[Jonathan M Davis]

On Thursday, November 15, 2012 17:18:43 foobar wrote:
> I thought that Haskell doesn't have function overloading (which
> simplifies this greatly)... Anyway, I mostly meant "standard"
> imperative/OO languages. Sorry for the confusion.

It has pattern matching (which typically results in several of the same 
function with slightly different arguments, but the overall types are still the 
same). I'm unaware of it having full-on function overloading. But I don't 
think that I've ever tried it.

- Jonathan M Davis