Aliasing lambdas
Timon Gehr
timon.gehr at gmx.ch
Sun Jan 13 12:54:04 PST 2013
On 01/13/2013 09:38 PM, Philippe Sigaud wrote:
> On Sun, Jan 13, 2013 at 9:07 PM, Timon Gehr <timon.gehr at gmx.ch> wrote:
>> On 01/13/2013 08:55 PM, Peter Alexander wrote:
>>>
>>> Is there any reason why this isn't allowed:
>>>
>>> alias f = (x => x);
>>>
>>> but this is:
>>>
>>> template A(alias B) { alias A = B; }
>>> alias f = A!(x => x);
>>>
>>> ???
>>
>>
>> No. It is a gratuitous grammar limitation.
>
> The same limitation forbids:
>
> alias __traits(whatever, ...) result;
>
> The grammar says:
>
> AliasDeclaration:
> alias BasicType Declarator
>
> (and others, but this is the one limiting you). BasicType should be
> replaced by PrimaryExrpession, or something like that.
>
I think it should be roughly:
alias TemplateArgument Identifier;
alias Identifier=TemplateArgument;
Note: The current grammar allows
alias int x = 2;
Which does not make any sense.
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