Make dur a property?

[Adam D. Ruppe]

On Wednesday, 23 January 2013 at 19:18:09 UTC, Johannes Pfau 
wrote:
> int DG() {return 42};
> int delegate() getDG() {return &DG};
>
> auto dg = getDG; //OK
> auto ??? = getDG();
>
> The last line could be a call to getDG with optional 
> parenthesis,
> so ??? = DG. Or it could be a call to getDG without optional
> parenthesis and a call to the returned DG, so ??? = 42.

If getDG is a @property, ??? == 42, because getDG() is rewritten 
into (getDG())() - parens there would ALWAYS mean "call the 
return value", so any @property is indistinguishable from its 
return value. (if we get @property like I want)

Without @property, it'd return DG because while parenthesis are 
optional, if they are present, they always apply to the preceding 
thing directly; getDG == getDG() in all cases. (This is the 
status quo, which I'd retain)


The type system will help catch errors here better than the 
syntax.